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Question

An electric dipole of length 2 cm, when placed with its axis making an angle of 60o with a uniform electric field, experiences a torque of 83 Nm. Calculate the potential energy of the dipole, if it has a charge of ± 4nC.

Solution
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Torque, τ=PEsin θ=2Qlsin θ

Here l is the length of the dipole, Q is the charge and E is the electric field.

Potential energy, U=PEcos θ=2Qlcos θ

τU=2Qlsinθ2Qlcosθ (where P=qd) =tanθτU=tanθU=τtan 600=833=8 joule

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