An electric field of 1000V-m is applied to an electric dipole angle of 45-o- The value of electric dipole moment is 10-29-C-m- What is the potential energy of the electric dipole-9times 10-20-J-7times 10-27-J-10times 10-29-J-20times 10-18-J

Question

Toppr Admin · Accepted Answer

U-x2212-x2192-P-x22C5-x2192-E-x2212-PEcos-x3B8-x2212-10-x2212-29-103-cos45o-x2212-0-707-xD7-10-x2212-26J-x2212-7-xD7-10-x2212-27J-

An electric field of $1000$ V/m is applied to an electric dipole at angle of $45^{o}$ . The value of electric dipole moment is $10^{- 29}$ C.m. What is the potential energy of the electric dipole?
$- 9 \times 10^{- 20}$ J
$- 7 \times 10^{- 27}$ J
$- 10 \times 10^{- 29}$ J
$- 20 \times 10^{- 18}$ J

$U = - \to P \cdot \to E$
$= - P E cos θ$
$= - (10^{- 29}) (10^{3}) cos 45^{o}$
$= - 0.707 \times 10^{- 26}$ J
$= - 7 \times 10^{- 27}$ J.

An electric field of 1000V/m is applied to an electric dipole at angle of 45o. The value of electric dipole moment is 10−29C.m. What is the potential energy of the electric dipole?−9×10−20J−7×10−27J−10×10−29J−20×10−18J

U=−→P⋅→E=−PEcosθ=−(10−29)(103)cos45o=−0.707×10−26J=−7×10−27J.

An electric field of $1000$ V/m is applied to an electric dipole at angle of $45^{o}$ . The value of electric dipole moment is $10^{- 29}$ C.m. What is the potential energy of the electric dipole?
$- 9 \times 10^{- 20}$ J
$- 7 \times 10^{- 27}$ J
$- 10 \times 10^{- 29}$ J
$- 20 \times 10^{- 18}$ J

$U = - \to P \cdot \to E$
$= - P E cos θ$
$= - (10^{- 29}) (10^{3}) cos 45^{o}$
$= - 0.707 \times 10^{- 26}$ J
$= - 7 \times 10^{- 27}$ J.