An electric field →E=(→i20+→j30)NC−1 exists in the space. If the potential at the origin is taken to be zero, find the potential at (2m,2m).
The electric field in the region is given by: E=(^i20+^j30)N/C
The position of the point is at (2m,2m)
The displacement vcector for the point is r=(2i+2j)
Therefore, the potential at the point is:
So, V=−→E×→r
=−(i20+30J)(2^i+2j)
=−(2×20+2×30)=−100V.