An electric heater calibrated $1.5 k W, 230 V$ is connected to a household branch circuit having $5$ A fuse wire and is, made to work. What will happen?

Question

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Answer 1

Given,
The power rating of the electric heater, $P = 1.5 k W = 1500 W$
Voltage, $V = 230 V$
Safe current rating of fuse wire, $I_{s a f e} = 5 A$

We know,
$P = V I$

$⟹ I = \frac{P}{V}$

$⟹ I = \frac{1 5 0 0}{2 3 0}$

$I = 6.52 A$

$I > I_{f u s e}$
$∴ t h e f u s e w i r e w i l l b u r n$

Answer 2

Given,

The power rating of the electric heater,

P = 1.5 k W = 1500 W

Voltage,

V = 230 V

Safe current rating of fuse wire,

I_{s a f e} = 5 A

We know,

P = V I

⟹ I = \frac{P}{V}

⟹ I = \frac{1 5 0 0}{2 3 0}

I = 6.52 A

I > I_{f u s e}

∴ t h e f u s e w i r e w i l l b u r n