An electric iron draws a current of 15 A from a 220 V supply. What is the cost of using iron for 30 min everyday for 15 days if the cost of unit (1 unit $=$ 1 k W hr) is 2 rupees?

Question

An electric iron draws a current of 15 A from a 220 V supply- What is the cost of using iron 30 min everyday 15 days the cost of unit -1 unit -1 kWhr- is 2 rupees - Rs 60Rs 40Rs 10Rs 49-5

Toppr Admin · Accepted Answer

As we know that power-P-v-xD7-Iso P-15-xD7-220-3300 wattcost per unit-2 rupees-xA0-therefore-3300-xD7-2-xD7-15-xD7-3060-xD7-1000-49-5 rupees-

An electric iron draws a current of 15 A from a 220 V supply, What is the cost of using iron for 30 min everyday for 15 days if the cost of unit (1 unit =1 kWhr) is 2 rupees ?
Rs 60
Rs 40
Rs 10
Rs 49.5

As we know that power(P)=v $\times$ I
so P=15 $\times$ 220=3300 watt
cost per unit=2 rupees
therefore, $\frac{3300 \times 2 \times 15 \times 30}{60 \times 1000}$ =49.5 rupees.

An electric iron draws a current of 15 A from a 220 V supply, What is the cost of using iron for 30 min everyday for 15 days if the cost of unit (1 unit =1 kWhr) is 2 rupees ? Rs 60Rs 40Rs 10Rs 49.5

As we know that power(P)=v×Iso P=15×220=3300 wattcost per unit=2 rupees therefore,3300×2×15×3060×1000=49.5 rupees.

An electric iron draws a current of 15 A from a 220 V supply, What is the cost of using iron for 30 min everyday for 15 days if the cost of unit (1 unit =1 kWhr) is 2 rupees ?
Rs 60
Rs 40
Rs 10
Rs 49.5

As we know that power(P)=v $\times$ I
so P=15 $\times$ 220=3300 watt
cost per unit=2 rupees
therefore, $\frac{3300 \times 2 \times 15 \times 30}{60 \times 1000}$ =49.5 rupees.