An electric iron is rated 750 W- 230 V- Calculate the electrical energy consumed by the iron in 16 hours-12 kWh43-2times 10-6 J120 kWh4-32times 10-6 J

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Toppr Admin · Accepted Answer

Energy consumed -750-xD7-16Wh-12000Wh-12kWhExpressed in joule-12kWh-12000-xD7-3600Ws-43-2-xD7-106J

An electric iron is rated at 750 W, 230 V. Calculate the electrical energy consumed by the iron in 16 hours.
12 kWh
$43.2 \times 10^{6}$ J
120 kWh
$4.32 \times 10^{6}$ J

Energy consumed $= 750 \times 16 W h = 12000 W h = 12 k W h$
Expressed in $j o u l e$ ,
$12 k W h = 12000 \times 3600 W s = 43.2 \times 10^{6} J$

An electric iron is rated at 750 W, 230 V. Calculate the electrical energy consumed by the iron in 16 hours.12 kWh43.2×106 J120 kWh4.32×106 J

Energy consumed =750×16Wh=12000Wh=12kWhExpressed in joule,12kWh=12000×3600Ws=43.2×106J

An electric iron is rated at 750 W, 230 V. Calculate the electrical energy consumed by the iron in 16 hours.
12 kWh
$43.2 \times 10^{6}$ J
120 kWh
$4.32 \times 10^{6}$ J

Energy consumed $= 750 \times 16 W h = 12000 W h = 12 k W h$
Expressed in $j o u l e$ ,
$12 k W h = 12000 \times 3600 W s = 43.2 \times 10^{6} J$