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Question

An electrical charge of 2 μC is placed at the point (1,2,3). At the point (2,3,4) the electric field and potential will be :
  1. 6×103NC1 and 6×103JC1
  2. 6000NC1 and 60003JC1
  3. 6×103NC1 and 33JC1
  4. none of the above

A
6000NC1 and 60003JC1
B
6×103NC1 and 6×103JC1
C
none of the above
D
6×103NC1 and 33JC1
Solution
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The electric field , E=14πϵ0qr2=9×109×2×106(21)2+(32)2+(43)2=6000NC1

and potential, V=14πϵ0qr=9×109×2×106(21)2+(32)2+(43)2=60003NC1

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