Solve

Guides

0

You visited us 0 times! Enjoying our articles? Unlock Full Access!

Question

An electron at point A in figure has a speed $v_{o} = 1.41 \times 10^{6} m / s$ . Find the time required for the electron to move from A to B.

Open in App

Solution

Verified by Toppr

Time period= $T = \frac{2 π r}{v} = 2.22 \times 10^{- 7} s$
Hence time taken by electron to move from A to B is $\frac{T}{2}$
$= 1.11 \times 10^{- 7} s$

Was this answer helpful?

1

Similar Questions

Q1

An electron at point A in figure has a speed

v_{o} = 1.41 \times 10^{6} m / s

. Find the time required for the electron to move from A to B.

View Solution

Q2

An electron at point A in figure has a speed

v_{o} = 1.41 \times 10^{6} m / s

. Find the magnitude and direction of the magnetic field that will cause the electron to follow the semicircular path from A to B,

View Solution

Q3

An electron at point A in the figure has a speed

V_{0}

of magnitude

1.41 \times 10^{6} m / s

. It enters into a uniform magnetic field and follows a semicircular path in it as shown.

The magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B is?

View Solution

Q4

An electron has a speed

\sqrt{2} \times 10^{6} m s^{- 1}

at

A

as shown in Fig. Find the direction and magnitude of magnetic field so that electron reaches

B

following a semicircular path.

View Solution

Q5

13.6 e V

is needed for ionisation of a hydrogen atom. An electron in a hydrogen atom in its ground state absorbs

1.50

times as much energy as the minimum energy required for it to escape from the atom. What is the wavelength and velocity of the emitted electron?

View Solution