0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

An electron in the ground state of hydrogen atom in revolving in anticlockwise direction in a circular orbit of radius R (see fig)
If the expression for the orbital magnetic moment of the electron is M=ehXπm. Find X?
168611.png

Solution
Verified by Toppr

In ground state (n=1) according to Bohr's theory:
mvR=h2π or v=h2πmR
Now time period, T=2πRv=2πRh/2πmR=4π2mR2h
Magnetic moment, M=iA
Where, I=chargetime period=e4π2mR2h=eh4π2mR2
and A=πR2
M=(πR2)(eh4π2mR2) or M=eh4πm
Direction of magnetic moment M is perpendicular to the plane of orbit.

Was this answer helpful?
5
Similar Questions
Q1
An electron in the ground state of hydrogen atom in revolving in anticlockwise direction in a circular orbit of radius R (see fig)
If the expression for the orbital magnetic moment of the electron is M=ehXπm. Find X?
168611.png
View Solution
Q2
An electron in the ground state of hydrogen atom is revolving in anticlockwise direction in a circular orbit of radius R.
Obtain an expression for the orbital magnetic moment of the electron.
1011826_3f801cacdf714459bca42581dd284860.jpg
View Solution
Q3
An electron in the ground state of Hydrogen atom is revolving in a circular orbit of radius R. Obtain the expression for the orbital magnetic moment of the electron.
View Solution
Q4
An electron in the ground state of hydrogen atom in revolving in anticlockwise direction in a circular orbit of radius R (see fig).
The atom is placed in a uniform magnetic induction B such that the normal to the plane of electron's orbit makes an angle of 30o with the magnetic induction. If the torque experienced by the orbiting electron is τ=ehBXπm. Find X?
168617.png
View Solution
Q5
An electron revolving in an orbit of radius 0.5˚A in a hydrogen atom executes 10 revolutions per second. The magnetic moment of electron due to its orbital motion will be :
View Solution