Question

# An electron is accelerated from rest through a potential difference of $$V$$ volt. If the de Broglie wavelength of the electron is $$1.227 \times 10^{-2} nm$$, the potential difference is :

A
$$10^2V$$
B
$$10^3V$$
C
$$10^4V$$
D
$$10V$$
Solution
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#### Correct option is C. $$10^4V$$The de-broglie wavelength of an electron is given as:$$\lambda=\dfrac{1.227}{\sqrt{V}}\ nm$$Substitute the wavelength in the above expression:$$V=\left(\dfrac{1.227}{1.227\times10^{-2}}\right)^2$$$$V=10^4\ V$$

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