Question

An electron is accelerated from rest through a potential difference of $$V$$ volt. If the de Broglie wavelength of the electron is $$1.227 \times 10^{-2} nm$$, the potential difference is :

A
$$10^2V$$
B
$$10^3V$$
C
$$10^4V$$
D
$$10V$$
Solution
Verified by Toppr

Correct option is C. $$10^4V$$
The de-broglie wavelength of an electron is given as:
$$\lambda=\dfrac{1.227}{\sqrt{V}}\ nm$$

Substitute the wavelength in the above expression:
$$V=\left(\dfrac{1.227}{1.227\times10^{-2}}\right)^2$$

$$V=10^4\ V$$

Was this answer helpful?
2
Similar Questions
Q1

What is the de Broglie wavelength associated with an electron, accelerated through a potential difference of 100 volts?


View Solution
Q2

The de-Broglie wavelength associated with an electron accelerated through a potential difference of 64 V is,

View Solution
Q3
An electron is accelerated from rest through a potential difference of 12.27 V. The de Broglie wavelength of the electron is
View Solution
Q4

How is the de-Broglie wavelength associated with an electron accelerated through a potential difference of 100 volts?

View Solution
Q5

De Broglie wavelength of an electron after being accelerated by a potential difference of V volt from rest is

View Solution
Solve
Guides