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An electron is accelerated from rest through a potential difference of $$V$$ volt. If the de Broglie wavelength of the electron is $$1.227 \times 10^{-2} nm$$, the potential difference is :

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Solution

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The de-broglie wavelength of an electron is given as:

$$\lambda=\dfrac{1.227}{\sqrt{V}}\ nm$$

Substitute the wavelength in the above expression:

$$V=\left(\dfrac{1.227}{1.227\times10^{-2}}\right)^2$$

$$V=10^4\ V$$

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