An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is 1.227×10−2nm, the potential difference is :
A
102V
B
103V
C
104V
D
10V
Medium
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Updated on : 2022-09-05
Solution
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Correct option is C)
The de-broglie wavelength of an electron is given as:
λ=V1.227nm
Substitute the wavelength in the above expression:
V=(1.227×10−21.227)2
V=104V
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