An electron is accelerated from rest through a potential difference of $$V$$ volt. If the de Broglie wavelength of the electron is $$1.227 \times 10^{-2} nm$$, the potential difference is :
A
$$10^2V$$
B
$$10^3V$$
C
$$10^4V$$
D
$$10V$$
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Solution
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Correct option is C. $$10^4V$$ The de-broglie wavelength of an electron is given as:
$$\lambda=\dfrac{1.227}{\sqrt{V}}\ nm$$
Substitute the wavelength in the above expression: