An electron is accelerated from rest through a potential difference of $$V$$ volt. If the de Broglie wavelength of the electron is $$1.227 \times 10^{-2} nm$$, the potential difference is :

Question

An electron is accelerated from rest through a potential difference of V volt- If the de Broglie wavelength of the electron is 1-227 times 10-2- nm- the potential difference is -

Toppr Admin · Accepted Answer

Correct option is C- -10-4V-The de-broglie wavelength of an electron is given as-lambda-dfrac-1-227-sqrt-V- nm-Substitute the wavelength in the above expression-V-left-dfrac-1-227-1-227-times10-2-right-2-V-10-4- V-

An electron is accelerated from rest through a potential difference of $$V$$ volt. If the de Broglie wavelength of the electron is $$1.227 \times 10^{-2} nm$$, the potential difference is :

Correct option is C. $$10^4V$$The de-broglie wavelength of an electron is given as:$$\lambda=\dfrac{1.227}{\sqrt{V}}\ nm$$Substitute the wavelength in the above expression:$$V=\left(\dfrac{1.227}{1.227\times10^{-2}}\right)^2$$$$V=10^4\ V$$

Correct option is C. $$10^4V$$
The de-broglie wavelength of an electron is given as:
$$\lambda=\dfrac{1.227}{\sqrt{V}}\ nm$$

Substitute the wavelength in the above expression:
$$V=\left(\dfrac{1.227}{1.227\times10^{-2}}\right)^2$$

$$V=10^4\ V$$