An electron is moving in a cyclotron at a speed of 3.2×107ms−1 in a magnetic field of 5×104T perpendicular to it. What is the frequency of this electron? (q=1.6×10−19 C, me=9.1×1031kg)
A
1.4 X 105Hz
B
1.4 X107Hz
C
1.4 X 106Hz
D
1.4 X 109Hz
Medium
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Solution
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Correct option is B)
V=3.2×107ms−1;B=5×10−4T
The frequency of electron is v=2πmqB=2×3.14×9.1×10−311.6×10−19×5×10−4
v=1.4×107Hz=14MHz
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