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# An electron is revolving in a circular path of radius 2.0×10−10 m with a uniform speed of 3×106m/s. The magnetic induction at the centre of the circular path will be0.6T1.2T0.12Tzero

A
0.6T
B
zero
C
0.12T
D
1.2T
Solution
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#### Current in the circular orbit: i=qv2πrMagnetic field at the center of a circular coil is B=μ0i2r=4π×10−7qv2πr2r=10−7×qvr2=10−71.6×10−19×3×10622×10−20=1.2T

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