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>>Magnetic Field on the Axis of a Circular Current Loop
>> $An electron is revolving in a circular p$

Question

An electron is revolving in a circular path of radius $2.0 \times 1 0^{- 10}$ m with a uniform speed of $3 \times 1 0^{6} m / s$ . The magnetic induction at the centre of the circular path will be

A

$0.6 T$

B

$1.2 T$

C

$0.12 T$

D

zero

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Updated on : 2022-09-05

Solution

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Correct option is B)

Current in the circular orbit: $i = \frac{q v}{2 π r}$
Magnetic field at the center of a circular coil is
$B = \frac{μ _{0} i}{2 r} = \frac{4 π \times 1 0 ^{- 7} \frac{q v}{2 π r}}{2 r} = 1 0^{- 7} \times \frac{q v}{r ^{2}} = 1 0^{- 7} \frac{1 . 6 \times 1 0 ^{- 19} \times 3 \times 1 0 ^{6}}{2 ^{2} \times 1 0 ^{- 20}} = 1.2 T$

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