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>> $An electron is shot in a steady electric$

Question

An electron is shot in a steady electric and magnetic field such that its velocity is $V$ . Electric field $E$ and magnetic field $B$ are mutually perpendicular. The magnitude of $E$ is $1 v o l t / c m$ and that of $B$ is $2 t e s l a$ . Now it happens that the Lorentz (Magnetic) force cancels with the electrostatic force on the electron , then the velocity of the electron is:

A

$50$ $m s^{- 1}$

B

$2$ $c m s^{- 1}$

C

$0.5$ $c m s^{- 1}$

D

$200$ $m s^{- 1}$

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Updated on : 2022-09-05

Solution

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Correct option is A)

$∵$ magnetic force cancels with the electrostatic force,
so $q E = q v B$
or, $V = \frac{E}{B}$ $= \frac{1 0 0}{2}$ $= 50 m s^{- 1}$

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