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# An electron is shot in a steady electric and magnetic field such that its velocity is V. Electric field E and magnetic field B are mutually perpendicular. The magnitude of E is 1 volt/cm and that of B is 2 tesla. Now it happens that the Lorentz (Magnetic) force cancels with the electrostatic force on the electron , then the velocity of the electron is:2 cms−150 ms−10.5 cms−1200 ms−1

A
2 cms1
B
0.5 cms1
C
50 ms1
D
200 ms1
Solution
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#### ∵ magnetic force cancels with the electrostatic force,so qE=qvBor, V=EB=1002=50 ms−1

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