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Question

An electron is shot in a steady electric and magnetic field such that its velocity is V. Electric field E and magnetic field B are mutually perpendicular. The magnitude of E is 1 volt/cm and that of B is 2 tesla. Now it happens that the Lorentz (Magnetic) force cancels with the electrostatic force on the electron , then the velocity of the electron is:
  1. 2 cms1
  2. 50 ms1
  3. 0.5 cms1
  4. 200 ms1

A
2 cms1
B
0.5 cms1
C
50 ms1
D
200 ms1
Solution
Verified by Toppr

magnetic force cancels with the electrostatic force,
so qE=qvB
or, V=EB=1002=50 ms1

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