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Question

An electron microscope is operated at 40Kv . The ratio of resolving power of this microscope and another one which uses yellow light of wavelength 6×107 is :
  1. 7×1025
  2. 9.78×104
  3. 9.78×104
  4. 9.78×106

A
9.78×104
B
9.78×106
C
7×1025
D
9.78×104
Solution
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Thereslovingpowerofamicrospcopeisinverselyproportinaltothewavelengthoflightused,forfirstelectronmicroscope,λ=h2meEλ=6.6×10342×9.11×1031×1.6×1019×40×103=3.5×1010mforsecondmicroscop,λ=cv=3×1086×107=0.5×1015mλλ=3.5×10100.5×1015=7×1025
Hence,
option (A) is correct answer.

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