An electron moves with a velocity vec-v- in an electric field vec-E- If the angle between vec-v- and vec-E- is neither 0 nor pi - then the path followed by the electron is a-an-circlestraight lineellipseparabola

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Toppr Admin · Accepted Answer

The perpendicular component of velocity is given by-vy-vsin-x3B8-Now in the X direction- the-xA0-electron experiences a force of E-x2212-e-So- -xA0-F-x2212-eEor-xA0-a-x2212-Eem

An electron moves with a velocity $\to v$ in an electric field $\to E$ . If the angle between $\to v$ and $\to E$ is neither 0 nor $π$ , then the path followed by the electron is a(an):
circle
straight line
ellipse
parabola

The perpendicular component of velocity is given by:
$v_{y} = v sin θ$
Now in the X direction, the electron experiences a force of $E (- e)$
So, $F = - e E$
or, $a = \frac{- E e}{m}$

An electron moves with a velocity →v in an electric field →E. If the angle between →v and →E is neither 0 nor π, then the path followed by the electron is a(an):circlestraight lineellipseparabola

The perpendicular component of velocity is given by:vy=vsinθNow in the X direction, the electron experiences a force of E(−e)So, F=−eEor, a=−Eem

An electron moves with a velocity $\to v$ in an electric field $\to E$ . If the angle between $\to v$ and $\to E$ is neither 0 nor $π$ , then the path followed by the electron is a(an):
circle
straight line
ellipse
parabola

The perpendicular component of velocity is given by:
$v_{y} = v sin θ$
Now in the X direction, the electron experiences a force of $E (- e)$
So, $F = - e E$
or, $a = \frac{- E e}{m}$