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>> $An electron of charge e mass m moves in$

Question

An electron of charge e mass m moves in an orbit of radius r with an angular velocity $ω$ . The ratio of the magnetic moment of the orbiting electron to its angular momentum is

A

e/m

B

2e/m

C

e/2m

D

2m/e

Medium

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Updated on : 2022-09-05

Solution

Verified by Toppr

Correct option is C)

angular momentum=mvr
= $m r^{2} ω$
magnetic moment
= $i . π . r^{2}$
= $(\frac{d q}{d t}) . π . r^{2}$
= $e . f . π . r^{2}$ = $e . (\frac{ω}{2 π}) . π . r^{2}$
= $\frac{e . ω . r ^{2}}{2}$
$\frac{M a g n e t i c m o m e n t}{A n g u l a r m o m e n t} = \frac{e}{2 m}$

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