An electron revolves around the nucleus of hydrogen atom in a circle of radius 5×10−11m. The intensity of electric field at a point in the orbit of the electron is:
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Correct option is A)
We know hydrogen atom consist of one proton and one electron R=5×10−11m We know attractive force =r2kq1(q2)=(5×10−11)29×109×(1⋅6×10−19)2 We know F=Eq ∴E=qF ∴E=5×10−11)29×109×(1⋅6×10−19)=5⋅76×1011N/C.
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