An electron travelling with a speed u along the positive x-axis enters into a region of magnetic field where $B = - B_{0} ˆ k (x > 0)$ . It comes out of the region with speed v then

Question

An electron travelling with a speed u along the positive x-axis enters into a region of magnetic field where

B = - B_{0} ˆ k (x > 0)

. It comes out of the region with speed v then

Toppr Admin · Accepted Answer

From Lorents equation-xA0-F-x2212-ev-x2C6-i-xD7-B0-x2212-x2C6-k-x2212-euB0-x2C6-jHence- it will complete a semicircular arc and comes out of the region at a position y- such that y -lt- 0-

An electron travelling with a speed u along the positive x-axis enters into a region of magnetic field where $B = - B_{0} ˆ k (x > 0)$ . It comes out of the region with speed v then
$v = u$ at y > 0
v > u at y < 0
$v = u$ at y < 0
v > u at y > 0

From Lorents equation: $F = - e v ˆ i \times B_{0} (- ˆ k) = - e u B_{0} ˆ j$
Hence, it will complete a semicircular arc and comes out of the region at a position y, such that y < 0.

An electron travelling with a speed u along the positive x-axis enters into a region of magnetic field where B=−B0ˆk(x>0). It comes out of the region with speed v thenv=u at y > 0v > u at y < 0v=u at y < 0v > u at y > 0

From Lorents equation: F=−evˆi×B0(−ˆk)=−euB0ˆjHence, it will complete a semicircular arc and comes out of the region at a position y, such that y < 0.

An electron travelling with a speed u along the positive x-axis enters into a region of magnetic field where $B = - B_{0} ˆ k (x > 0)$ . It comes out of the region with speed v then
$v = u$ at y > 0
v > u at y < 0
$v = u$ at y < 0
v > u at y > 0

From Lorents equation: $F = - e v ˆ i \times B_{0} (- ˆ k) = - e u B_{0} ˆ j$
Hence, it will complete a semicircular arc and comes out of the region at a position y, such that y < 0.