An ideal gas occupying a volume of 2 dm-3- and a pressure of 5 bar undergoes isothermal and irreversible expansion against external pressure of 1 bar- The final volume of the system and the work involved in the process is10 dm-3- - 1000J8dm-3- -800 J10 dm-3- -800J10m-3- -1000J

Question

Toppr Admin · Accepted Answer

Vi-2dm3-P-5barVf-P1V1Pf-5-xD7-21-10dm3Work done-x2212-Pext-Vf-x2212-Vi-x2212-1-10-x2212-2-1-xD7-105Pa-xD7-8-xD7-10-x2212-3m3-x2212-800J

An ideal gas occupying a volume of 2 dm3 and a pressure of 5 bar undergoes isothermal and irreversible expansion against external pressure of 1 bar. The final volume of the system and the work involved in the process is10 dm3 , 1000J8dm3, -800 J10 dm3, -800J10m3, -1000J

Vi=2dm3,P=5barVf=P1V1Pf=5×21=10dm3Work done=−Pext(Vf−Vi)=−(1)(10−2)=1×105Pa×8×10−3m3=−800J

$V_{i} = 2 d m^{3}, P = 5 b a r$
$V_{f} = \frac{P_{1} V_{1}}{P_{f}} = \frac{5 \times 2}{1} = 10 d m^{3}$
Work done $= - P_{e x t} (V_{f} - V_{i})$
$= - (1) (10 - 2)$
$= 1 \times 10^{5} P a \times 8 \times 10^{- 3} m^{3}$
$= - 800 J$