An infinite number of electric charges each equal to $5 \times 10^{- 9} C$ are placed along X – axis at x = 1 cm, x = 3 cm, x = 9 cm, x =27 cm ………. And so on. If the consecutive charges have opposite sign,
Then the electric field in $\frac{N}{C}$ at x = 0 is $(\frac{1}{4 π ϵ_{0}} = 9 \times 10^{9} N m^{2} / C^{2})$

Question

An infinite number of electric charges each equal to

5 \times 10^{- 9} C

are placed along X – axis at x = 1 cm, x = 3 cm, x = 9 cm, x =27 cm ………. And so on. If the consecutive charges have opposite sign,
Then the electric field in

\frac{N}{C}

at x = 0 is

(\frac{1}{4 π ϵ_{0}} = 9 \times 10^{9} N m^{2} / C^{2})

Toppr Admin · Accepted Answer

An infinite number of electric charges each equal to 5 nano-coulomb (magnitude) are placed along X-axis at x= 1 cm, x= 2 cm, x = 4cm, x = 8 cm .... ...............and so on. In the setup if the consecutive charges have opposite sign, then find the electric field at x = 0. G =9x10 N-m 70) TEO