An isolated capacitor with a capacitance $C$ has a potential difference between the plates of $V$ , which leaves on each plate a charge $Q$ .
A dielectric is then pulled out from in-between the plates, what effect does this have on energy stored in the isolated capacitor?
The energy is increased.
The energy is not affected.
There is not enough information given to answer this question.
The energy is decreased.

Question

An isolated capacitor with a capacitance $C$ has a potential difference between the plates of $V$ , which leaves on each plate a charge $Q$ .
A dielectric is then pulled out from in-between the plates, what effect does this have on energy stored in the isolated capacitor?
The energy is increased.
The energy is not affected.
There is not enough information given to answer this question.
The energy is decreased.

Toppr Admin · Accepted Answer

Capacitance in between the plates is given by-xA0-C-KA-x3F5-0dHence the capacitance decreases on removing dielectric from the region between the plates-When capacitor is isolated- the charge becomes constant- Hence the energy stored in capacitor Q22C increases-

Capacitance in between the plates is given by C=KAϵ0dHence the capacitance decreases on removing dielectric from the region between the plates.When capacitor is isolated, the charge becomes constant. Hence the energy stored in capacitor Q22C increases.

Capacitance in between the plates is given by
$C = \frac{K A ϵ_{0}}{d}$
Hence the capacitance decreases on removing dielectric from the region between the plates.
When capacitor is isolated, the charge becomes constant. Hence the energy stored in capacitor $\frac{Q^{2}}{2 C}$ increases.