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Question

An isolated metallic object is charged in vacuum to a potential $$V_0$$, its electrostatic energy being $$W_0$$. It is then disconnected from the source of potential, its charge being lift unchanged and is immersed in a large volume of dielectric, with dielectric constant K. The electrostatic energy will be?

A
$$K W_0$$
B
$$W_0/K$$
C
$$W_0$$
D
$$\dfrac{W_0}{2K}$$
Solution
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Correct option is B. $$W_0/K$$

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