An object 15 cm high is placed 10 cm from the optical center of a thin lens- Its image is formed 25 cm from the optical center on the same side of the lens as the object- The height of the image is-2-5 cm0-2 cm37-5 cm16-7 cm

Question

Toppr Admin · Accepted Answer

Height of image is magnification-xD7-heightobject-vu-xD7-15-15-xD7-2510-37-5option D is correct-xA0-

An object $15 c m$ high is placed $10 c m$ from the optical center of a thin lens. Its image is formed $25 c m$ from the optical center on the same side of the lens as the object. The height of the image is:
$2.5 c m$
$0.2 c m$
$37.5 c m$
$16.7 c m$

height of image is $m a g n i f i c a t i o n \times h e i g h t_{o b j e c t} = \frac{v}{u} \times 15 = 15 \times \frac{25}{10} = 37.5$
option $D$ is correct

An object 15cm high is placed 10cm from the optical center of a thin lens. Its image is formed 25cm from the optical center on the same side of the lens as the object. The height of the image is:2.5cm0.2cm37.5cm16.7cm

height of image is magnification×heightobject=vu×15=15×2510=37.5option D is correct

An object $15 c m$ high is placed $10 c m$ from the optical center of a thin lens. Its image is formed $25 c m$ from the optical center on the same side of the lens as the object. The height of the image is:
$2.5 c m$
$0.2 c m$
$37.5 c m$
$16.7 c m$

height of image is $m a g n i f i c a t i o n \times h e i g h t_{o b j e c t} = \frac{v}{u} \times 15 = 15 \times \frac{25}{10} = 37.5$
option $D$ is correct