Question

An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Find the position and nature of the image.

Answer 1

Given: $f=15$

$u=-10$

From mirror formula, $\frac{1}{u}+\frac{1}{v}=\frac{1}{f}$

$\frac{1}{-10}+\frac{1}{v}=\frac{1}{15}$

$v=6cm$

Image is formed 6 cm to the right of the mirror. Image formed is virtual and erect.