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>> $An object is placed at a distance of 200$

Question

An object is placed at a distance of $200 c m$ from a combination of two equal lenses of equal power of $+ 1 D$ . The distance of the image of the object for system is:

A

$33.33 c m$

B

$- 33.33 c m$

C

$66.67 c m$

D

$40 c m$

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Updated on : 2022-09-05

Solution

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Correct option is D)

$P = P_{1} + P_{2} = 2 D$
$f = \frac{1}{2} m = 50 c m$
$\frac{1}{u} + \frac{1}{v} = \frac{1}{f}$
$\frac{1}{v} = \frac{1}{f} - \frac{1}{u}$
$= \frac{1}{5 0} - \frac{1}{- 2 0 0} = \frac{1}{4 0}$
$v = 40 c m$

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