An object is placed a distance of 30 cm from a concave mirror and its real image is formed a distance of 30 cm from the mirror- The focal length of the mirror is -45 cm15 cm60 cm30 cm

Question

Toppr Admin · Accepted Answer

Given-xA0-Object distance - u-30cm and image distance v-30cmIf f be the focal length- 1-f-1-u-1-v-1-30-1-30-1-15 or f-15cm

An object is placed at a distance of $30 c m$ from a concave mirror and its real image is formed at a distance of $30 c m$ from the mirror. The focal length of the mirror is :
$45 c m$
$15 c m$
$60 c m$
$30 c m$

Given,

Object distance , $u = + 30 c m$ and image distance $v = + 30 c m$

If $f$ be the focal length, $1 / f = 1 / u + 1 / v = 1 / 30 + 1 / 30 = 1 / 15$ or $f = 15 c m$

An object is placed at a distance of 30cm from a concave mirror and its real image is formed at a distance of 30cm from the mirror. The focal length of the mirror is :45cm15cm60cm30cm

Given, Object distance , u=+30cm and image distance v=+30cmIf f be the focal length, 1/f=1/u+1/v=1/30+1/30=1/15 or f=15cm

An object is placed at a distance of $30 c m$ from a concave mirror and its real image is formed at a distance of $30 c m$ from the mirror. The focal length of the mirror is :
$45 c m$
$15 c m$
$60 c m$
$30 c m$

Given,

Object distance , $u = + 30 c m$ and image distance $v = + 30 c m$

If $f$ be the focal length, $1 / f = 1 / u + 1 / v = 1 / 30 + 1 / 30 = 1 / 15$ or $f = 15 c m$