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>> $An object is taken to height 2R above th$

Question

An object is taken to height 2R above the surface of earth, the increase in potential energy is [R is radius of earth]

A

$\frac{m g R}{2}$

B

$\frac{m g R}{3}$

C

$\frac{2 m g R}{3}$

D

2 mgR

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Updated on : 2022-09-05

Solution

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Correct option is C)

Change in gravitational potential energy at a height h above the earth's surface is $△ U = \frac{m g h}{1 + ( \frac{h}{r} )}$
$= \frac{m g . 2 R}{1 + \frac{2 R}{R}}$ [here,h=2R]
= $\frac{2 m g R}{3}$

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