An object, moving with a speed of 6.25 m/s, is decelerated at a rate given by: dvdt=−2.5√v where v is the instantaneous speed. The time taken by the object, to come to rest, would be:

An object, moving with a speed of 6.25 m/s, is decelerated at a rate given by: dvdt=−2.5√v where v is the instantaneous speed. The time taken by the object, to come to rest, would be:

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Q2

An object, moving with a speed 6.25ms−1, is decelerated at a rate given by dvdt=−2.5√v where v is intantaneous velocity. The time taken by the object to come to rest would be: