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>>Class 11
>>Physics
>>Motion in a Straight Line
>>Acceleration
>> $An object, moving with a speed of 6.25 m$

Question

An object, moving with a speed of 6.25 m/s, is decelerated at a rate given by:
$\frac{d v}{d t} = - 2.5 v$ where v is the instantaneous speed. The time taken by the object, to come to rest, would be:

A

2 s

B

4 s

C

8 s

D

1 s

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Updated on : 2022-09-05

Solution

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Correct option is A)

$A c c o r d i n g t o q u e s t i o n . . . . . . . . . . . . . . . . . . . \int_{6.25}^{0} (\frac{d v}{v}) = - 2.5 \int_{0}^{t} d t \Rightarrow ∣ 2 v ∣_{6.25}^{0} = - 2.5 t \Rightarrow 2 . 6.25 = 2.5 t ∴ t = 2 s s o t h e c o r r e c t o p t u o n i s A$

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