An object of height 6 cm is placed perpendicular to the principal axis of a concave lens of focal length 5 cm. Use lens formula to determine the position, size and nature of the image if the distance of the object from the lens is 10 cm.
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Given : u=−10 cm f=−5 cm ho=6 cm
Using lens formula : v1−u1=f1
⟹v=−310=−3.33 cm (- sign shows that image is virtual)
⟹hi=+2 cm (+ sign shows that image is erect)
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