0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

# An object of mass $$10kg$$ is projected from ground with speed $$40m/s$$ at an angle $$60^0$$ with horizontal the rate of change of momentum of object one second after projection in SI unit is [Take $$g=9.8m/s^2$$]

Solution
Verified by Toppr

#### According to intial data we have$$v_x=40\cos60$$ (const)$$v_y=40\sin60-(9.8)(1)$$$$v_y=40\cdot\frac{\sqrt{3}}{2}(9.8)(1)$$Change in momentum = $$m(v_y+v_x)4m(v_y+v_x)$$$$=m(40\sin60-9.8+40\cos60)$$$$=m(40\sin60+4\cos60)$$$$=m(9.8)$$$$=9.8$$

0
Similar Questions
Q1
An object of mass $$10kg$$ is projected from ground with speed $$40m/s$$ at an angle $$60^0$$ with horizontal the rate of change of momentum of object one second after projection in SI unit is [Take $$g=9.8m/s^2$$]
View Solution
Q2
An object of mass 10 kg is projected from ground with speed 40 m/s at an angle 60o with horizontal. The rate of change of momentum of object one second after projection in SI unit is [Take g=9.8m/s2]
View Solution
Q3
An object is projected from ground with speed 20m/s at angle 30 with horizontal. Its centripetal acceleration one second after the projection is [Take g=10m/s2]
View Solution
Q4
A body of mass 1 kg is projected from ground at an angle 30o with horizontal on a level ground at a speed 50 m/s. The magnitude of change in momentum of the body during its flight is (g=10 m/s2)
View Solution
Q5
An object is projected with speed 50 m/s at an angle 53 with horizontal from ground. The radius of curvature of its trajectory at t=1 sec after projection will be:
(Take g=10 m/s2)
View Solution