An object starting from rest travels with a uniform acceleration of 5 m-s-2 -Calculate the velocity and distance traveled after 1 minute-

Question

An object starting from rest travels with a uniform acceleration of  5 m-s-2 -Calculate the velocity and distance traveled after  1 minute-

Toppr Admin · Accepted Answer

- v-u-at - u-0 - 0- 5m-s-2-times 60s - a- 5m-s-2 - 0-300 m-s - t-1- min -So- - t-60 sec - 300 m-s - s- ut -1-2 at-2 - 0 -times 60 - 1-2 -times 5 -times 60-2- 9000 m -

An object starting from rest travels with a uniform acceleration of $$ 5 m/s^2 $$.Calculate the velocity and distance traveled after $$ 1$$ minute?

$$ v=u+at $$
$$ u=0 $$
=$$ 0+ 5m/s^2\times 60s $$
$$ a= 5m/s^2 $$
=$$ 0+300 m/s $$

$$ t=1\ min $$
So, $$ t=60 sec $$
=$$ 300 m/s $$

$$ s= ut +1/2 at^2 $$
=$$ 0 \times 60 + 1/2 \times 5 \times 60^2$$
=$$ 9000 m $$

An object starting from rest travels with a uniform acceleration of $$ 5 m/s^2 $$.Calculate the velocity and distance traveled after $$ 1$$ minute?

$$ v=u+at $$$$ u=0 $$=$$ 0+ 5m/s^2\times 60s $$$$ a= 5m/s^2 $$=$$ 0+300 m/s $$$$ t=1\ min $$So, $$ t=60 sec $$=$$ 300 m/s $$$$ s= ut +1/2 at^2 $$=$$ 0 \times 60 + 1/2 \times 5 \times 60^2$$=$$ 9000 m $$

$$ v=u+at $$
$$ u=0 $$
=$$ 0+ 5m/s^2\times 60s $$
$$ a= 5m/s^2 $$
=$$ 0+300 m/s $$

$$ t=1\ min $$
So, $$ t=60 sec $$
=$$ 300 m/s $$

$$ s= ut +1/2 at^2 $$
=$$ 0 \times 60 + 1/2 \times 5 \times 60^2$$
=$$ 9000 m $$