u=−20 ; f=+10
So, from 1v−1u=1f, we get:
v=+20
Magnification: vu=−1............ (i)
Hence vertical velocity of image is same as that of object but in reverse direction.
Let the horizontal velocity be VIx
We have: v=fuu−f
Differentiating w.r.t. time, we get:
VIx=f2(u−f)2×Vobject
⇒ VIx=Vobject [using (i)]
Hence angle made by velocity vector of image is −π4