Question

An oil drop of 12 excess electrons is held stationary under a constant electric field of in Millikans oil drop experiment. The density of the oil is . Estimate the radius of the drop. [g = 1.60 C].

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Excess electrons on an oil drop,

Electric field intensity,

Density of oil,

Acceleration due to gravity,

Charge on an electron,

Radius of the oil drop

Force (F) due to electric field E is equal to the weight of the oil drop (W).

Where, Net charge on the oil drop = ne

Mass of the oil drop

      Volume of the oil drop × Density of oil

     

Therefore, the radius of the oil drop is .

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Physics Part-I
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