An Olympic swimming pool is in the shape of a cuboid of dimensions $50 m$ long and $25 m$ . wide. If it is $3 m$ deep throughout, how many liters of water does it hold?
$(1 c u . m = 1000 l i t e r s)$

Question

Toppr Admin · Accepted Answer

Given- an Olympic swimming pool is shape of a cuboid of dimensions 50 m long- 25 m wide and it is 3 m deepThen volume of cuboid - length-xD7-width-xD7-height-50-xD7-25-xD7-3-3750 cu- mSo- the water in swimming pool - volume of swimming pool -3750 liters

An Olympic swimming pool is in the shape of a cuboid of dimensions $50$ m long and $25$ m wide. If it is $3$ m deep throughout, how many liters of water does it hold?
$3750$ liters
$3775$ liters
$3800$ liters
$3850$ liters

Given, an Olympic swimming pool is shape of a cuboid of dimensions $50$ m long, $25$ m wide and it is $3$ m deep
Then volume of cuboid $=$ $length \times width \times height = 50 \times 25 \times 3 = 3750$ cu. m
So, the water in swimming pool $=$ volume of swimming pool $= 3750$ liters

An Olympic swimming pool is in the shape of a cuboid of dimensions 50 m long and 25 m wide. If it is 3 m deep throughout, how many liters of water does it hold?3750 liters3775 liters3800 liters 3850 liters

Given, an Olympic swimming pool is shape of a cuboid of dimensions 50 m long, 25 m wide and it is 3 m deepThen volume of cuboid = length×width×height=50×25×3=3750 cu. mSo, the water in swimming pool = volume of swimming pool =3750 liters

An Olympic swimming pool is in the shape of a cuboid of dimensions $50$ m long and $25$ m wide. If it is $3$ m deep throughout, how many liters of water does it hold?
$3750$ liters
$3775$ liters
$3800$ liters
$3850$ liters

Given, an Olympic swimming pool is shape of a cuboid of dimensions $50$ m long, $25$ m wide and it is $3$ m deep
Then volume of cuboid $=$ $length \times width \times height = 50 \times 25 \times 3 = 3750$ cu. m
So, the water in swimming pool $=$ volume of swimming pool $= 3750$ liters