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- π/4
- π/2
- 3π/4
- π

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Solution

Verified by Toppr

The curved surface of the cylindrical can be made by rolling the sheet and there will be no weste of material. But in order to have the base of the can, which will be circular of radius r we will have to cut it from a square metal sheet 2r by 2r and whose area will be 4r2 whereas the actual area of the base is only πr2.But no allowance is to be made for waste of material. Hence the total surface area of the sheet used for making the open cylindrical can is S=2πrh+4r2

Also V=πr2h(given)∴h=V/πr2

∴S=2πr.Vπr2+4r2=2Vr+4r2

∴dsdr=−2Vr2+8r=0or4r3=V

d2Sdr2=4Vr3+8=4.4+8=24+ive;

hence minimum when 4r3=V=πr2h∴r/h=π/4 is the required ratio.

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