An ore contains 20 - zinc - How many kg of ore will be required to get 45 kg of zinc -

Question

Toppr Admin · Accepted Answer

In ore-160-Zinc - 20 -160-Consider x as the quantity of ore-160-we can write it as-160-20 - - of- x - 45 -so we get-160- -dfrac-20 -100- -times x - 45 -Here-160-dfrac x5 - 45- x - 45 -times 5 - 225 -Hence- the quantity of ore is 225 kg-

An ore contains 20 % zinc . How many kg of ore will be required to get 45 kg of zinc ?

In ore
Zinc = 20 %
Consider x as the quantity of ore
we can write it as
$$20 \% \ of\ x = 45 $$
so we get
$$ \dfrac{20 }{100} \times x = 45 $$
Here
$$\dfrac x5 = 45$$
$$ x = 45 \times 5 = 225 $$
Hence, the quantity of ore is 225 kg.

An ore contains 20 % zinc . How many kg of ore will be required to get 45 kg of zinc ?

In ore Zinc = 20 % Consider x as the quantity of ore we can write it as $$20 \% \ of\ x = 45 $$so we get $$ \dfrac{20 }{100} \times x = 45 $$Here $$\dfrac x5 = 45$$$$ x = 45 \times 5 = 225 $$Hence, the quantity of ore is 225 kg.

In ore
Zinc = 20 %
Consider x as the quantity of ore
we can write it as
$$20 \% \ of\ x = 45 $$
so we get
$$ \dfrac{20 }{100} \times x = 45 $$
Here
$$\dfrac x5 = 45$$
$$ x = 45 \times 5 = 225 $$
Hence, the quantity of ore is 225 kg.