An organic compound $$(C_8 H_{10} O_2)$$ rotates plane-polarized light. It produces pink color with neutral $$FeCl_3$$ solution. What is the total number of all the possible isomers for this compound?
Correct option is A. 6
Since compound $$C_8 H_{10} O_2$$ corresponds positively to neutral $$FeCl_3$$. Hence it will be a phenol compound.
Hence total optically active isomers will be $$6$$.