An organic compound undergoes first-order decomposition. The time taken for its decomposition to 1/8 and 1/10 of its initial concentration are $t_{1 / 8}$ and $t_{1 / 10}$ respectively. What is the value of $\frac{t_{1 / 8}}{t_{1 / 10}} \times 10$ ? (take $1 o g_{10} 2 = 0.3$ )

Question

An organic compound undergoes first-order decomposition. The time taken for its decomposition to 1/8 and 1/10 of its initial concentration are

t_{1 / 8}

and

t_{1 / 10}

respectively. What is the value of

\frac{t_{1 / 8}}{t_{1 / 10}} \times 10

? (take

1 o g_{10} 2 = 0.3

)

Toppr Admin · Accepted Answer

T18-2-303-xD7-log8k-2-303-xD7-3log2k-xA0- -xA0-Note - -log11-8-log8-

An organic compound undergoes first-order decomposition. The time taken for its decomposition to 1/8 and 1/10 of its initial concentration are $t_{1 / 8}$ and $t_{1 / 10}$ respectively. What is the value of $\frac{t_{1 / 8}}{t_{1 / 10}} \times 10$ ? (take $1 o g_{10} 2 = 0.3$ )
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