An organic compound -X- on treatment with acidified K-2Cr-2O-7 gives a compound -Y- which reacts with I-2 and Na-2CO-3 to form tri-iodomethane- The compound -X- is-

Question

Toppr Admin · Accepted Answer

Correct option is D- -CH-3CHOHCH-3-The compound Y should be a ketone as it is responding to iodoform test- Since it is formed by treating X with potassium dichromate-acidic- X should be a secondary alcohol- X is-160-CH-3CH-OH-CH-3-

An organic compound 'X' on treatment with acidified $$K_2Cr_2O_7$$ gives a compound 'Y' which reacts with $$I_2$$ and $$Na_2CO_3$$ to form tri-iodomethane. The compound 'X' is?

Correct option is D. $$CH_3CHOHCH_3$$
The compound Y should be a ketone as it is responding to iodoform test. Since it is formed by treating X with potassium dichromate(acidic) X should be a secondary alcohol. X is $$CH_3CH(OH)CH_3$$

An organic compound 'X' on treatment with acidified $$K_2Cr_2O_7$$ gives a compound 'Y' which reacts with $$I_2$$ and $$Na_2CO_3$$ to form tri-iodomethane. The compound 'X' is?

Correct option is D. $$CH_3CHOHCH_3$$The compound Y should be a ketone as it is responding to iodoform test. Since it is formed by treating X with potassium dichromate(acidic) X should be a secondary alcohol. X is $$CH_3CH(OH)CH_3$$

Correct option is D. $$CH_3CHOHCH_3$$
The compound Y should be a ketone as it is responding to iodoform test. Since it is formed by treating X with potassium dichromate(acidic) X should be a secondary alcohol. X is $$CH_3CH(OH)CH_3$$