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Question

An ornament piece is made of gold and copper.Its total weight is $$96$$gms.If $$\dfrac{1}{12}$$ of the ornament is copper.Find the weight of gold in it.

Solution
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Total weight$$=96$$g
Weight of copper$$=\dfrac{1}{12}$$ of $$96$$
$$=\dfrac{1}{12}\times 96=8$$gms
$$\therefore\,$$Weight of gold$$=$$Total weight$$-$$Weight of copper$$=96-8=88$$gms

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