AngleABC and angleBDC are two right angles- If AD-9cm- DC-16cm and AB-15cm- then the length of BD is -12cm16cm25cm15cm

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Toppr Admin · Accepted Answer

-x2220-BDA-x2220-BDC-90o-x2234-x25B3-ABD is a rightangled triangle-Thus- AB2-BD2-AD2-x21D2-152-BD2-92-x21D2-BD2-225-x2212-81-144-x21D2-BD-x221A-144-12cm

$∠$ ABC and $∠$ BDC are two right angles. If AD $= 9$ cm, DC $= 16$ cm and AB $= 15$ cm, then the length of BD is __________.

$12$ cm
$16$ cm
$25$ cm
$15$ cm

$∠ B D A = ∠ B D C = 90^{o}$
$∴ △ A B D$ is a rightangled triangle.
Thus, $A B^{2} = B D^{2} + A D^{2}$
$\Rightarrow 15^{2} = B D^{2} + 9^{2} \Rightarrow B D^{2} = 225 - 81 = 144 \Rightarrow B D = \sqrt{144} = 12 c m$

∠ABC and ∠BDC are two right angles. If AD=9cm, DC=16cm and AB=15cm, then the length of BD is __________.12cm16cm25cm15cm

∠BDA=∠BDC=90o∴△ABD is a rightangled triangle.Thus, AB2=BD2+AD2⇒152=BD2+92⇒BD2=225−81=144⇒BD=√144=12cm

$∠$ ABC and $∠$ BDC are two right angles. If AD $= 9$ cm, DC $= 16$ cm and AB $= 15$ cm, then the length of BD is __________.

$12$ cm
$16$ cm
$25$ cm
$15$ cm

$∠ B D A = ∠ B D C = 90^{o}$
$∴ △ A B D$ is a rightangled triangle.
Thus, $A B^{2} = B D^{2} + A D^{2}$
$\Rightarrow 15^{2} = B D^{2} + 9^{2} \Rightarrow B D^{2} = 225 - 81 = 144 \Rightarrow B D = \sqrt{144} = 12 c m$