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Answer the following question
In the following nuclear reaction
$n +_{92}^{235} U \to_{Z}^{144} B a +_{36}^{A} X + 3 n,$
Assign the values of Z and A.

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Updated on : 2022-09-05

Solution

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$n +_{92}^{235} U \to_{Z}^{144} B a +_{36}^{A} X + 3 n,$
From law of conservation of atomic number
$0 + 92 = Z + 36$
$\Rightarrow Z = 92 - 36 = 56$
From law of conservation of mass number,
$1 + 235 = 144 + A + 3 \times 1$
$A = 236 - 147 = 89$

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