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# A parallel beam of light of wavelength 600 nm is incident normally on a slit of width d. If the distance between the slits and the screen is 0.8 m and the distance of 2nd order maximum from the center of the screen is 15 mm. The width of the slit is 40 μm80 μm200 μm160 μm

A
40 μm
B
80 μm
C
200 μm
D
160 μm
Solution
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#### Distance of 2nd order maximum form the centre of the screen x=52DλdHere, D=0.8m,x=15mm=15×10−3mλ=600nm=600nm=600×10−9m∴d=52⋅Dλx=52×0.8×600×10−915×10−3=80μm

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