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Question

A parallel beam of light of wavelength 600 nm is incident normally on a slit of width d. If the distance between the slits and the screen is 0.8 m and the distance of 2nd order maximum from the center of the screen is 15 mm. The width of the slit is
  1. 40 μm
  2. 80 μm
  3. 200 μm
  4. 160 μm

A
40 μm
B
80 μm
C
200 μm
D
160 μm
Solution
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Distance of 2nd order maximum form the centre of the screen
x=52Dλd
Here, D=0.8m,x=15mm=15×103m

λ=600nm=600nm=600×109m

d=52Dλx=52×0.8×600×10915×103=80μm

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