Aqueous NaOH- P - 4 -left- white right- longrightarrow P- H - 3 -X- Compound X is-N- a - 2 -C- O - 3 -N- a - 2 -HP- O - 4 -NaHC- O - 3 -Na- H - 2 -P- O - 2 -

Question

Toppr Admin · Accepted Answer

The reaction is-xA0-P4-3NaOH-3H2O-x2192-PH3-3NaH2PO2White phosphorus react with sodium hydroxide and water to produce phosphine and sodium hypophosphite - Sodium hydroxide - cold- concentrated solution- This reaction takes place slow-Hence option A is correct answer-

aqueous $N a O H + P_{4} (w h i t e) ⟶ P H_{3} + X .$ Compound X is:
$N a_{2} C O_{3}$
$N a_{2} H P O_{4}$
$N a H C O_{3}$
$N a H_{2} P O_{2}$

The reaction is,
$P_{4} + 3 N a O H + 3 H_{2} O \to P H_{3} + 3 N a H_{2} P O_{2}$
White phosphorus react with sodium hydroxide and water to produce phosphine and sodium hypophosphite . Sodium hydroxide - cold, concentrated solution. This reaction takes place slow.

Hence option A is correct answer.

aqueous NaOH+P4(white)⟶PH3+X. Compound X is:Na2CO3Na2HPO4NaHCO3NaH2PO2

The reaction is, P4+3NaOH+3H2O→PH3+3NaH2PO2White phosphorus react with sodium hydroxide and water to produce phosphine and sodium hypophosphite . Sodium hydroxide - cold, concentrated solution. This reaction takes place slow.Hence option A is correct answer.

aqueous $N a O H + P_{4} (w h i t e) ⟶ P H_{3} + X .$ Compound X is:
$N a_{2} C O_{3}$
$N a_{2} H P O_{4}$
$N a H C O_{3}$
$N a H_{2} P O_{2}$