Are the rational numbers dfrac-8-28- and dfrac-32-112- equivalent- Give reason-

Question

Toppr Admin · Accepted Answer

Standard form of given rational numbers-Rightarrow -dfrac-8-28-dfrac-8-247-4-28-247-4-dfrac-2- -7-dfrac-32-112-dfrac-32-247-16-112-247-16-dfrac-2-7-Therefore- the standard form of given numbers are equal that is -dfrac-2-7-

Are the rational numbers $$\dfrac{-8}{28}$$ and $$\dfrac{32}{-112}$$ equivalent? Give reason.

Standard form of given rational numbers
$$\Rightarrow \dfrac{-8}{28}=\dfrac{-8÷4}{28÷4}=\dfrac{-2} {7}$$
$$=\dfrac{32}{-112}=\dfrac{32÷16}{-112÷16}=\dfrac{-2}{7}$$
Therefore, the standard form of given numbers are equal that is $$\dfrac{-2}{7}.$$

Are the rational numbers $$\dfrac{-8}{28}$$ and $$\dfrac{32}{-112}$$ equivalent? Give reason.

Standard form of given rational numbers$$\Rightarrow \dfrac{-8}{28}=\dfrac{-8÷4}{28÷4}=\dfrac{-2} {7}$$$$=\dfrac{32}{-112}=\dfrac{32÷16}{-112÷16}=\dfrac{-2}{7}$$Therefore, the standard form of given numbers are equal that is $$\dfrac{-2}{7}.$$

Standard form of given rational numbers
$$\Rightarrow \dfrac{-8}{28}=\dfrac{-8÷4}{28÷4}=\dfrac{-2} {7}$$
$$=\dfrac{32}{-112}=\dfrac{32÷16}{-112÷16}=\dfrac{-2}{7}$$
Therefore, the standard form of given numbers are equal that is $$\dfrac{-2}{7}.$$