Arrange −59,712,−23 and 1118 in ascending order of their magnitudes. Identify the smallest
Consider the given numbers −59,712,−23 and 1118.
The LCM of the denominators 9,12,3,18 is 36. Therefore, the given numbers will be:
−5×49×4=−20367×312×3=2136−2×123×12=−243611×218×2=2236
Thus, the numbers in ascending order are shown below:
−2436,−2036,2136,2236⇒−23,−59,712,1118