Arrange in ascending order of magnitude $\sqrt{3}, \sqrt[5]{15}, \sqrt[10]{227}$
$\sqrt[5]{15} < \sqrt[10]{227} < \sqrt{3}$
$\sqrt{3} < \sqrt[5]{15} < \sqrt[10]{227}$
None of these
$\sqrt[10]{227} < \sqrt{3} < \sqrt[5]{15}$

Question

Arrange in ascending order of magnitude sqrt 3- sqrt -5-15- sqrt -10-227-sqrt -5-15- - sqrt -10-227- - sqrt 3sqrt 3 - sqrt -5-15- - sqrt -10-227-None of thesesqrt -10-227- - sqrt 3 - sqrt -5-15-

Toppr Admin · Accepted Answer

-x221A-3-5-x221A-15-10-x221A-227LCM of 2-5 and 10-10

Arrange in ascending order of magnitude √3,5√15,10√2275√15<10√227<√3√3<5√15<10√227None of these10√227<√3<5√15

√3,5√15,10√227LCM of 2,5 and 10=10

Arrange in ascending order of magnitude $\sqrt{3}, \sqrt[5]{15}, \sqrt[10]{227}$
$\sqrt[5]{15} < \sqrt[10]{227} < \sqrt{3}$
$\sqrt{3} < \sqrt[5]{15} < \sqrt[10]{227}$
None of these
$\sqrt[10]{227} < \sqrt{3} < \sqrt[5]{15}$

$\sqrt{3}, \sqrt[5]{15}, \sqrt[10]{227}$

LCM of $2, 5$ and $10 = 10$