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Arrange the following carbanions in decreasing order of stabilus P CH2=CH Q. Ph-CH, R. CHA-CH-CHS A) P>Q>R>S (B) S> > >R (C) S> >> P (D) QS>R>p

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Similar Questions

Q1

A)

C H_{3} - C H_{2} - \oplus C H_{2}

B)

C H_{3} - C H | F - \oplus C H_{2}

C)

C H_{3} - C H | B r - \oplus C H_{2}

D)

C H_{3} - C H | C l - \oplus C H_{2}

Arrange the following carbocations in decreasing order of their stability:

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Q2

Arrange the following in decreasing order of basic strength :

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Q3

Arrange the following compounds in order of decreasing ease of abstraction of hydrogen atom:
(a)

{C H}_{2} = {C H}_{2}

(b)

{C H}_{2} = C H {C H}_{3}

(c)

C_{6} H_{5} {C H}_{3}

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Q4

Consider the following carbanions.
I)

C H_{3} - C H_{2}^{-}

II)

C H_{2} = C H^{-}

III)

C H \equiv - C

Correct order of stability of these carbanions in decreasing order is:

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Q5

In the reaction:

P h - C H = C H - C H_{2} B r H O H - -- \to [X]

[X]

would be:

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