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Question

Arrange the following gases in the increasing order of their van der Waals constant $$a$$ values :
$$CO_2$$, $$H_2$$, $$C_6H_6$$

Solution
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$$H_2 < CO_2 < C_6H_6$$

as
$$a_H=0.246 \ atm\ liter^2mol^{-2}$$
$$a_{CO_2}=3.640 \ atm\ liter^2mol^{-2}$$
$$a_{C_6H_6}=18.24 \ atm\ liter^2mol^{-2}$$

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