$$893245, 893425$$ and $$980134$$ are $$6-$$digits number
$$980134$$ is the largest number
The same numbers in the remaining two numbers are $$8, 9$$ and $$3$$ are placed at lakhs, ten thousands and thousands places respectively and the digits $$2$$ and $$4$$ are at hundreds place
Hence $$893245 < 893425$$
$$1020304, 1021403$$ and $$1020216$$ are all $$7-$$digits number
Since they have the same digits at ten lakhs, lakhs and ten thousand places namely $$1,0$$ and $$2$$ respectively
$$1021403$$ has $$1$$ at thousand places and the remaining two numbers have the digits at hundred places namely $$2$$ and $$3$$
Since $$2 < 3$$
$$\therefore 1020216 < 1020304$$
Hence, the given numbers in ascending order are
$$893245 < 893425 < 980134 < 1020216 < 1020304 < 1021403$$